# Rbse solution for Class 5 Maths Chapter 3 How Many Squares

ncert solution for Class 5 Maths Chapter 3e: 34

1.

(i) Measure the side of the square on dotted sheet. Draw here as many rectangles as possible using 12 such squares.

Solution:-

The side of the square on dotted sheet is 1 cm.

(ii) How many rectangles could you make?

Solution:-ncert solution for Class 5 Maths Chapter 3

We can make 7 rectangle.

2. Each rectangle is made out of 12 equal squares, so all have the same area, but the length of the boundary will be different.

(i) Which of these rectangles has the longest perimeter?

Solution:-

From the above figure we can say that, rectangle 1 and 2 has the longest perimeter.

We know that, perimeter of rectangle= 2 (length + breadth)

= 2 (1 + 12)

= 2 × 13

= 26 cm

(ii) Which of these rectangles has the smallest perimeter?

Solution:-

From the above figure we can say that, rectangle 3, rectangle 4, rectangle 5 and 6 rectangle has the smallest perimeter.

We know that, perimeter of rectangle= 2 (length + breadth)

= 2 (3 + 5)

= 2 × 8

= 16 cm

3.

Look at these interesting stamps.

(a) How many squares of one centimetre side does stamp A cover? ________

And stamp B? ________

Solution:-

Stamp A covers 18 squares of one centimeter side, and Stamp B covers 8 squares of one centimeter side.

(b) Which stamp has the biggest area?

Solution:-

Stamp ‘A’ has biggest area, because it has 18 squares.

(i) How many squares of side 1 cm does this stamp cover?

Solution:-

This stamp has 18 squares of side 1 cm.

(ii) How much is the area of the biggest stamp?

Solution:-

The biggest stamp is in the shape of rectangle,

The area of the biggest stamp is = length × breadth

= 3 × 6

= 18 cm2

c) Which two stamps have the same area?

Solution:-

Stamp ‘D’ and stamp ‘F’ have the same area.

(i) How much is the area of each of these stamps? ____ square cm.

Solution:-

We know that, area of rectangle = length × breadth

So, Area of stamp ‘D’ = 3 × 4

= 12 cm2

Area of stamp ‘F’ = 4 × 3

= 12 cm2

Therefore area of stamp ‘D’ is equal to area of stamp ‘F’.

d) The area of the smallest stamp is _____ square cm.

Solution:-

The area of the smallest stamp is 4 square cm.

area of smallest stamp ‘E’ = length × breadth

= 2 × 2

= 4 cm2

(i) The difference between the area of the smallest and the biggest stamp is _____ square cm.

Solution:-

Area of the biggest stamp = 18 cm2

Area of the smallest stamp = 4 cm2

Then,

The difference between the area of the smallest and the biggest stamp = 18 – 4

= 14 cm2

4. Guess

a) Which has the bigger area — one of your footprints or the page of this book?

Solution:-

When comparing the area of footprints and the area of page of this book, the area of page of this book is bigger than footprints.

b) Which has the smaller area—two five-rupee notes together or a hundred rupee note?

Solution:-

A hundred rupee note has the smaller area.

c) Look at a 10 rupee-note. Is its area more than hundred square cm?

Solution:-

No, the area of 10 rupee note is not more than hundred square cm.

d) Is the area of the blue shape more than the area of the yellow shape? Why?

Solution:-

No, from the given image we can say that, the area of blue shape is equal to the area of yellow shape. Because, the yellow and blue shaped figures are divided into two triangles of equal areas.

e) Is the perimeter of the yellow shape more than the perimeter of the blue shape? Why?

Solution:-

No, the perimeter of the yellow shape is less than the perimeter of the blue shape. With the help of a ruler, we can able find that the length of the boundary of the blue shape is more than the length of the boundary of the yellow shape.

5. Write the area (in square cm) of the shapes below.

Solution:-

Area of triangle fig A = ½ × base × height

= ½ × 3 × 4

= ½ × 12

= 6 cm2

Area of square fig B = 4 complete square + 8 half squares + 4 quarter squares

= 4 + (½ × 8) + (¼ × 4)

= 4 + 4 + 1

= 9 cm2

Area of fig C = 2 complete square + 4 half square

= 2 + (½ × 4)

= 2 + 2

= 4 cm2

Area of fig D = 5 complete square + 2 half square

= 5 + (½ × 2)

= 5+ 1

= 6 cm2

Area of fig E = 18 complete square + 6 half square

= 18 + (½ × 6)

= 18 + 3

= 21 cm2

Area of fig F = 4 complete square + 4 more than half + 4 quarter square

= 4 + (¾ × 4) + (¼ × 4)

= 4 + 3 + 1

= 8 cm2

6. The blue triangle is half of the big rectangle. Area of the big rectangle is 20 square cm. So the area of the blue triangle is _______ square cm.

Solution:-

From the question,

Area of the big rectangle is 20cm2.

Area of the blue triangle is half of the big rectangle = 20/2

= 10 cm2

7. Ah, in it there are two halves of two different rectangles!

Now you find the area of the two rectangles Sadiq is talking about. What is the area of the red triangle? Explain.

From the figure, we can say that,

The orange rectangle contains 12 squares

So, area of orange rectangle = 12 cm2

Then, green rectangle contains 8 squares

So, the area of green rectangle = 8 cm2

Now, area of the orange portion of triangle = 12/2 = 6cm2

Area of the yellow portion of triangle = 8/2 = 4 cm2

Therefore, area of red triangle = 6 + 4

= 10 cm2

8. Suruchi drew two sides of a shape. She asked Asif to complete the shape with two more sides, so that its area is 10 square cm.

He completed the shape like this.

(i) Is he correct? Discuss.

Solution:-

Yes, he is correct.

(ii) Explain how the green area is 4 square cm and the yellow area is 6 square cm.

Solution:-

Green area contains = 2 complete square + 4 half square

= 2 + (½ × 4)

= 2 + 2

= 4 cm2

Yellow area contains = 3 complete square + 2 more than half + 2 half filled

= 3 + 2 + (½ × 2)

= 3 + 2 + 1

= 6 cm2

Practice time

(1) This is one of the sides of a shape. Complete the shape so that its area is 4 square cm.

Solution:-

The completed shape contains = 2 complete square + 4 half square

= 2 + (½ × 4)

= 2 + 2

= 4 cm2

2. Two sides of a shape are drawn here. Complete the shape by drawing two more sides so that its area is less than 2 square cm.

Solution:-

3. Here is a rectangle of area 20 square cm.

a) Draw one straight line in this rectangle to divide it into two equal triangles. What is the area of each of the triangles?

Solution:-

Area of rectangle = 10 × 2

= 20 cm2

Then, area of two equal triangles = 20/2

= 10 cm2

Because, it is given that straight line divides rectangle in to two equal triangles.

b) Draw one straight line in this rectangle to divide it into two equal rectangles. What is the area of each of the smaller rectangles?

Solution:-

Area of big rectangle = 10 cm2

The area of each of the smaller rectangle = 20/2

= 10 cm2

c) Draw two straight lines in this rectangle to divide it into one rectangle and two equal triangles.

Solution:-

(i) What is the area of the rectangle?

Solution:-

Area of rectangle = length × breadth

= 2 × 5

= 10 cm2

(ii) What is the area of each of the triangles?

Solution:-

Area of each triangle = ½ × area of smaller rectangle

= ½ × 10

= 5 cm2

4. Puzzle with five squares

a) How many different shapes can you draw?

Solution:-

Using 5 squares, I can draw 12 shapes as show in the below,

b) Which shape has the longest perimeter? How much?

Solution:-

Shape 4 has the smallest perimeter out of 12 shapes, rest of the shapes have same perimeter. i.e. = 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1 + 1 + 1 + 1 + 1 = 12 cm

c) Which shape has the shortest perimeter? How much?

Solution:-

Out of 12 shapes 4 has the smallest perimeter.

i.e. = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 10 cm.

d) What is the area of the shapes? _______ square cm. That’s simple!

Solution:-

There are 12 shapes each shapes has complete five squares. Area of 1 square is equal to 1 cm2.

So, Area of each shape = 1 × 5 = 5 cm2

5. Ziri tried to make some other tiles. She started with a square of 2 cm side and made shapes like these.

Look at these carefully and find out:

(i) Which of these shapes will tile a floor (without any gaps)? Discuss. What is the area of these shapes?

Solution:-

By observing the given figure shape C and shape D will tile a floor without any gaps.

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