RBSE Solutions for Class 6 MATHS Chapter 6: Integers

RBSE Solutions for Class 6 MATHS Chapter 6: Integers

RBSE Solutions for Class 6 MATHS Chapter 6 :Embarking on the mathematical journey of Class 6 in the Rajasthan Board of Secondary Education (RBSE), students encounter the intriguing realm of integers in Chapter 6. Titled “Integers,” this chapter lays the foundation for understanding positive and negative numbers, introducing concepts crucial for advanced mathematical learning. To aid students in mastering this essential topic, we present comprehensive RBSE solutions that unravel the complexities of integers. Let’s delve into the key concepts and discover how our solutions can make the study of integers a seamless experience.

Access RBSE Solutions for Class 6 Chapter 6: Integers

RBSE Solutions for Class 6 MATHS Chapter 6 Exercise 6.1 page no: 120

1. Write opposites of the following.

(a) Increase in weight

(b) 30 km north

(c) 80 m east

(d) Loss of Rs 700

(e) 100 m above sea level

Solutions:

(a) The opposite of an increase in weight is a decrease in weight.

(b) The opposite of 30 km north is 30 km south.

(c) The opposite of 80 m east is 80 m west.

(d) The opposite of a loss of Rs 700 is a gain of Rs 700.

(e) The opposite of 100 m above sea level is 100 m below sea level.

2. Represent the following numbers as integers with appropriate signs.

(a) An aeroplane is flying at the height of two thousand metres above the ground.

(b) A submarine is moving at a depth of eight hundred metres below sea level.

(c) A deposit of rupees two hundred.

(d) Withdrawal of rupees seven hundred.

Solutions:

(a) + 2000 m

(b) – 800 m

(c) + Rs 200

(d) – Rs 700

3. Represent the following numbers on a number line.

(a) + 5

(b) – 10

(c) + 8

(d) – 1

(e) – 6

Solutions:

(a) + 5

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 1

(b) – 10

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 2

(c) + 8

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 3

(d) – 1

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 4

(e) – 6

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 5

4. Adjacent figure is a vertical number line representing integers. Observe it and locate the following points.

(a) If point D is + 8, then which point is – 8?

(b) Is point G a negative integer or a positive integer?

(c) Write integers for points B and E.

(d) Which point marked on this number line has the least value?

(e) Arrange all the points in decreasing order of value.

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 6

Solutions:

(a) If point D is +8, then point F is -8.

(b) Point G is a negative integer.

(c) Point B is 4, and point E is – 10.

(d) The least value on this number line is point E, as it represents – 10.

(e) The points in decreasing order of value are D, C, B, A, O, H, G, F, E.

5. Following is the list of temperatures of five places in India on a particular day of the year.

Place Temperature

Siachin 10°C below 0°C ……………..

Shimla 2°C below 0°C ……………..

Ahmedabad 30°C above 0°C ……………..

Delhi 20°C above 0°C ……………..

Srinagar 5°C below 0°C ……………..

(a) Write the temperatures of these places in the form of integers in the blank column.

(b) Following is the number line representing the temperature in degree Celsius.

Plot the name of the city against its temperature.

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 7

(c) Which is the coolest place?

(d) Write the names of the places where temperatures are above 10°C.

Solutions:

(a)

Siachin – 100 C

Shimla – 20 C

Ahmedabad + 300 C

Delhi + 200 C

Srinagar – 50 C

(b)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 8

(c) Siachin is the coolest place.

(d) Ahmedabad and Delhi are the places where the temperatures are above 100C.

6. In each of the following pairs, which number is to the right of the other on the number line?

(a) 2, 9

(b) – 3, – 8

(c) 0, – 1

(d) – 11, 10

(e) – 6, 6

(f) 1, – 100

Solutions:

(a) 9 lies to the right on the number line (9 > 2).

(b) – 3 lies to the right on the number line (- 3 > – 8).

(c) 0 lies to the right on the number line (0 > -1).

(d) 10 lies to the right on the number line (10 > -11).

(e) 6 lies to the right on the number line (6 > -6).

(f) 1 lies to the right on the number line (1 > -100).

7. Write all the integers between the given pairs (write them in increasing order).

(a) 0 and – 7

(b) – 4 and 4

(c) – 8 and – 15

(d) – 30 and – 23

Solutions:

(a) -6, -5, -4, -3, -2, -1 are the integers between 0 and -7.

(b) -3, -2, -1, 0, 1, 2, 3 are the integers between -4 and 4.

(c) -14, -13, -12, -11, -10, -9 are the integers between -8 and -15.

(d) -29, -28, -27, -26, -25, -24 are the integers between -30 and -23.

8. (a) Write four negative integers greater than – 20.

(b) Write four integers less than – 10.

Solutions:

(a) -19, -18, -17, -16 are the integers greater than -20.

(b) -11, -12, -13, -14 are the integers less than -10.

9. For the following statements, write True (T) or False (F). If the statement is false, correct the statement.

(a) – 8 is to the right of – 10 on a number line.

(b) – 100 is to the right of – 50 on a number line.

(c) Smallest negative integer is – 1.

(d) – 26 is greater than – 25.

Solutions:

(a) True, as (-8 > -10).

(b) False. (-50 is greater than -100). Hence, -100 lies to the left of -50 on the number line.

(c) False. -1 is the greater negative integer.

(d) False. -26 is smaller than -25.

10. Draw a number line and answer the following.

(a) Which number will we reach if we move 4 numbers to the right of – 2?

(b) Which number will we reach if we move 5 numbers to the left of 1?

(c) If we are at – 8 on the number line, in which direction should we move to reach – 13?

(d) If we are at – 6 on the number line, in which direction should we move to reach – 1?

Solutions:

(a)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 9

If we move 4 numbers to the right of -2, we will reach 2.

(b)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 10

If we move 5 numbers to the left of 1, we will reach -4.

(c)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 11

-13 lies to the left of -8 on the number line. Hence, we should move towards the left direction.

(d)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.1 - 12

-1 lies to the right of -6 on the number line. So, we should move towards the right direction.


RBSE Solutions for Class 6 MATHS Chapter 6 Exercise 6.2 Page no: 128

1. Using the number line, write the integer which is:

(a) 3 more than 5

(b) 5 more than –5

(c) 6 less than 2

(d) 3 less than –2

Solutions:

(a)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 - 1

Hence, 8

(b) 

Hence, 0

(c)
NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 - 3

Hence, -4

(d)
NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 - 4

Hence, -5

2. Use a number line and add the following integers.

(a) 9 + (–6)

(b) 5 + (–11)

(c) (–1) + (–7)

(d) (–5) + 10

(e) (–1) + (–2) + (–3)

(f) (–2) + 8 + (–4)

Solutions:

(a)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 - 5

Hence, 3

(b)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 - 6

Hence, -6

(c)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 - 7

Hence, -8

(d)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 - 8

Hence, 5

(e)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 - 9

Hence, -6

(f)

NCERT Solutions for Class 6 Maths Chapter 6 Exercise 6.2 - 10

Hence, 2

3. Add without using a number line.

(a) 11 + (–7)

(b) (–13) + (+18)

(c) (–10) + (+19)

(d) (–250) + (+150)

(e) (–380) + (–270)

(f) (–217) + (–100)

Solutions:

(a) 11 + (-7) = 4

(b) (-13) + (+18) = 5

(c) (-10) + (+19) = 9

(d) (-250) + (+150) = -100

(e) (-380) + (-270) = -650

(f) (-217) + (-100) = -317

4. Find the sum of:

(a) 137 and – 354

(b) – 52 and 52

(c) – 312, 39 and 192

(d) – 50, – 200 and 300

Solutions:

(a) 137 and -354

(137) + (-354) = (137) + (-137) + (-217)

= 0 + (-217) [(137) + (-137) = 0]

= (-217)

= -217

(b) -52 and 52

(-52) + (+52) = 0 [(-a) + (+a) = 0]

(c) -312, 39 and 192

(-312) + (+39) + (+192) = (-231) + (-81) + (+39) + (+192)

= (-231) + (-81) + (+231)

= (-231) + (+231) + (-81)

= 0 + (-81) [(-a) + (+a) = 0]

= -81

(d) -50, -200 and 300

(-50) + (-200) + (+300) = (-50) + (-200) + (+200) + (+100)

= (-50) + 0 + (+100) [(-a) + (+a) = 0]

= (-50) + (+100)

= (-50) + (+50) + (+50)

= 0 + (+50) [(-a) + (+a) = 0]

= 50

5. Find the sum.

(a) (–7) + (–9) + 4 + 16

(b) (37) + (–2) + (–65) + (–8)

Solutions:

(a) (-7) + (-9) + 4 + 16

= (-7) + (-9) + 4 + (+7) + (+9)

= (-7) + (+7) + (-9) + (+9) + 4

= 0 + 0 + 4 [(-a) + (+a) = 0]

= 4

(b) (37) + (-2) + (-65) + (-8)

= (+37) + (-75)

= (+37) + (-37) + (-38)

= 0 + (-38) [(-a) + (+a) = 0]

= -38


RBSE Solutions for Class 6 MATHS Chapter 6 Exercise 6.3 page no: 131

1. Find

(a) 35 – (20)

(b) 72 – (90)

(c) (-15) – (-18)

(d) (-20) – (13)

(e) 23 – (-12)

(f) (-32) – (-40)

Solutions:

(a) 35 – (20)

35 – 20

15

(b) 72 – (90)

= 72 – 90

= -18

(c) (-15) – (-18)

= -15 + 18

= 3

(d) (-20) – (13)

= -20 – 13

= -33

(e) 23 – (-12)

= 23 + 12

= 35

(f) (-32) – (-40)

= -32 + 40

= 8

2. Fill in the blanks with >, < or = sign.

(a) (–3) + (–6) ______ (–3) – (–6)

(b) (–21) – (–10) _____ (–31) + (–11)

(c) 45 – (– 11) ______ 57 + (– 4)

(d) (–25) – (–42) _____ (– 42) – (–25)

Solutions:

(a) (-3) + (-6) = -9

(-3) – (-6) = -3 + 6 = 3

-9 < 3

Therefore, (-3) + (-6) < (-3) – (-6)

(b) -21 – (-10) = -21 + 10 = -11

-31 + (-11) = -42

-11 > -42

Therefore, (-21) – (-10) > (-31) + (-11)

(c) 45 – (-11) = 45 + 11 = 56

57 + (-4) = 57 – 4 = 53

56 > 53

Therefore, 45 – (-11) > 57 + (-4)

(d) (-25) – (-42) = -25 + 42 = 17

-42 – (-25) = -42 + 25 = -17

17 > -17

Therefore, (-25) – (-42) > (-42) – (-25)

3. Fill in the blanks.

(a) (–8) + _____ = 0

(b) 13 + _____ = 0

(c) 12 + (–12) = ____

(d) (–4) + ____ = –12

(e) ____ – 15 = – 10

Solutions:

(a) (-8) + 8 = 0

(b) 13 + (-13) = 0

(c) 12 + (-12) = 0

(d) (-4) + (-8) = -12

(e) 5 – 15 = -10

4. Find

(a) (–7) – 8 – (–25)

(b) (–13) + 32 – 8 – 1

(c) (–7) + (–8) + (–90)

(d) 50 – (–40) – (–2)

Solutions:

(a) (-7) – 8 – (-25) = -7 -8 + 25

= -15 + 25

= 10

(b) (-13) + 32 – 8 – 1 = -13 + 32 – 8 – 1

= 32 – 22

= 10

(c) (-7) + (-8) + (-90) = -7 – 8 – 90

= – 105

(d) 50 – (-40) – (-2) = 50 + 40 + 2

= 92

Conclusion:

As students delve into the world of integers in RBSE Class 6 Maths Chapter 6, our SEO-friendly article emphasizes the significance of understanding positive and negative numbers. Our comprehensive solutions not only guide students through problem-solving but also provide conceptual clarity, a step-by-step approach, and real-life applications to make the learning experience enriching. Unlocking the potential of integers is a key milestone in mathematical education, and our solutions are designed to make this journey both enjoyable and academically rewarding for RBSE Class 6 students.

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