RBSE Solutions For Class 7 Maths Chapter 6 – The Triangle and its Properties

Exercise 6.1 Solutions

Exercise 6.3 Solutions

Exercise 6.4 Solutions

Exercise 6.5 Solutions

Access Answers to NCERT Class 7 Maths Chapter 6 – The Triangle and its Properties Exercise 6.2

1. Find the value of the unknown exterior angle x in the following diagram:

(i)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 8

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 50+ 70o

= x = 120o

(ii)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 9

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 65+ 45o

= x = 110o

(iii)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 10

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 30+ 40o

= x = 70o

(iv)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 11

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 60+ 60o

= x = 120o

(v)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 12

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 50+ 50o

= x = 100o

(vi)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 13

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 30+ 60o

= x = 90o

2. Find the value of the unknown interior angle x in the following figures:

(i)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 14

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x + 50o = 115o

By transposing 50o from LHS to RHS it becomes – 50o

= x = 115o – 50o

= x = 65o

(ii)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 15

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= 70o + x = 100o

By transposing 70o from LHS to RHS it becomes – 70o

= x = 100o – 70o

= x = 30o

(iii)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 16

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

The given triangle is a right angled triangle. So the angle opposite to the x is 90o.

= x + 90o = 125o

By transposing 90o from LHS to RHS it becomes – 90o

= x = 125o – 90o

= x = 35o

(iv)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 17

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x + 60o = 120o

By transposing 60o from LHS to RHS it becomes – 60o

= x = 120o – 60o

= x = 60o

(v)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 18

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

The given triangle is a right angled triangle. So the angle opposite to the x is 90o.

= x + 30o = 80o

By transposing 30o from LHS to RHS it becomes – 30o

= x = 80o – 30o

= x = 50o

(vi)

NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and Its Properties Image 19

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

The given triangle is a right angled triangle. So the angle opposite to the x is 90o.

= x + 35o = 75o

By transposing 35o from LHS to RHS it becomes – 35o

= x = 75o – 35o

= x = 40o

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  1. Pingback: RBSE Solutions for Class 7 Chapter 6 – The Triangle and its Properties Exercise 6.5 - ncert solutions

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