# RBSE Solutions For Class 7 Maths Chapter 6 – The Triangle and its Properties

Exercise 6.1 Solutions

Exercise 6.3 Solutions

Exercise 6.4 Solutions

Exercise 6.5 Solutions

### Access Answers to NCERT Class 7 Maths Chapter 6 – The Triangle and its Properties Exercise 6.2

1. Find the value of the unknown exterior angle x in the following diagram:

(i)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 50+ 70o

= x = 120o

(ii)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 65+ 45o

= x = 110o

(iii)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 30+ 40o

= x = 70o

(iv)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 60+ 60o

= x = 120o

(v)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 50+ 50o

= x = 100o

(vi)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x = 30+ 60o

= x = 90o

2. Find the value of the unknown interior angle x in the following figures:

(i)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x + 50o = 115o

By transposing 50o from LHS to RHS it becomes – 50o

= x = 115o – 50o

= x = 65o

(ii)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= 70o + x = 100o

By transposing 70o from LHS to RHS it becomes – 70o

= x = 100o – 70o

= x = 30o

(iii)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

The given triangle is a right angled triangle. So the angle opposite to the x is 90o.

= x + 90o = 125o

By transposing 90o from LHS to RHS it becomes – 90o

= x = 125o – 90o

= x = 35o

(iv)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

= x + 60o = 120o

By transposing 60o from LHS to RHS it becomes – 60o

= x = 120o – 60o

= x = 60o

(v)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

The given triangle is a right angled triangle. So the angle opposite to the x is 90o.

= x + 30o = 80o

By transposing 30o from LHS to RHS it becomes – 30o

= x = 80o – 30o

= x = 50o

(vi)

Solution:-

We Know That,

An exterior angle of a triangle is equal to the sum of its interior opposite angles.

The given triangle is a right angled triangle. So the angle opposite to the x is 90o.

= x + 35o = 75o

By transposing 35o from LHS to RHS it becomes – 35o

= x = 75o – 35o

= x = 40o

### 2 thoughts on “RBSE Solutions For Class 7 Maths Chapter 6 – The Triangle and its Properties”

Patio umbrellas sold at Costco recalled after reports of fires गर्मी में लू लगने से बचाव करेंगे यह खाद्य पदार्थ, आज ही खाना करें शुरू ट्रेन के बीच में ही AC कोच क्यों लगाए जाते हैं? Rbse books for class 1 to 12 hindi medium 2021-22