Rbse Solutions for Class 10 Maths Chapter 10 Exercise 10.1 | Circles

Get complete, step-by-step solutions for NCERT Class 10 Maths Chapter 10 Exercise 10.1 on Circles. Solutions cover the fundamental concepts of tangents and secants, including defining a tangent and a secant, identifying the point of contact, and determining the maximum number of parallel tangents a circle can have (Q.1, Q.2). Practice applying the property that the radius is perpendicular to the tangent at the point of contact to calculate the length of a tangent using the Pythagorean theorem (Q.3). Includes instructions for drawing a circle with parallel tangent and secant lines (Q.4). Essential for building a strong foundation in circle geometry.

1. How many tangents can a circle have?

A circle can have infinitely many tangents.

Justification: A tangent touches the circle at exactly one point, and there are infinitely many points on the circumference of a circle.


2. Fill in the blanks:

(i) A tangent to a circle intersects it in one point(s).

(ii) A line intersecting a circle in two points is called a secant.

(iii) A circle can have two parallel tangents at the most.

(iv) The common point of a tangent to a circle and the circle is called the point of contact.


3. Length PQ

Let $P$ be the point of contact, $O$ be the center, and $PQ$ be the tangent.

The radius $OP = 5 \text{ cm}$. The distance from the center to $Q$ is $OQ = 12 \text{ cm}$.

Since the radius is perpendicular to the tangent at the point of contact, $\triangle OPQ$ is a right-angled triangle with the right angle at $P$ ($\angle OPQ = 90^\circ$). $OQ$ is the hypotenuse.

Rbse Solutions for Class 10 Maths Chapter 10 Exercise 10.1 | Circles

Using the Pythagorean theorem:

$$OP^2 + PQ^2 = OQ^2$$

$$5^2 + PQ^2 = 12^2$$

$$25 + PQ^2 = 144$$

$$PQ^2 = 144 – 25$$

$$PQ^2 = 119$$

$$PQ = \sqrt{119} \text{ cm}$$

The correct option is (D) $\sqrt{119} \text{ cm}$.

(Note: The textbook options often write the number under the root without the root sign as a typo, but $\sqrt{119}$ is the correct answer based on the calculation.)


4. Draw a circle and two lines parallel to a given line

  • Step 1: Draw a circle with center $O$ and any radius $r$.
  • Step 2: Draw a given line $l$.
  • Step 3: Draw a line $m$ parallel to $l$ that passes through two points of the circle (a secant).
  • Step 4: Draw a line $n$ parallel to $l$ that touches the circle at exactly one point, say $A$ (a tangent).
Rbse Solutions for Class 10 Maths Chapter 10 Exercise 10.1 | Circles

Last Updated on November 28, 2025 by Aman Singh

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  • Aman Singh

    Aman Singh | M.Sc. Mathematics, RRBMU University Alwar

    A seasoned Mathematics Educator with 7 years of dedicated experience in the field of education. Specializing in simplifying complex mathematical concepts, Aman has a proven track record of helping students master advanced topics. Holds an M.Sc. in Mathematics from RRBMU University, Alwar. Passionate about leveraging conceptual clarity and effective teaching methodologies to drive student success and achievement.

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